Consider the foillowing code:

public class OverloadExample $\{$

public int multiply$($int a$,$ int b$)\{$

return a $*$ b;

$\}$

public double multiply$($double a$,$ double b$)\{$

return a $*$ b;

$\}$

public static void main$($String$[]$ args$)\{$

OverloadExample example $=$ new OverloadExample$()$;

System.out.println$($example$.$multiply$(2,3))$;

System.out.println$($example$.$multiply$(2\mathrm{.}5,3\mathrm{.}5))$;

$\}$

$\}$

What happens if you try to call example.multiply $(2,3\mathrm{.}5)?$

Explain which method would be called and why.

What will be the output of the following line?

System.out.println$($example$.$multiply$(2,3))$;

Explain why this output is produced.

$($I need new answers$)$