Question: Consider the following algorithm (A[1..n] is an array of numbers): for i = 1 to n -1 { min = i; for j = i+1
-
Consider the following algorithm (A[1..n] is an array of numbers):
for i = 1 to n -1 { min = i;
for j = i+1 to n do { if (A[j] < A[min])
min = j;
}
swap(A[i], A[min]) // exchange their contents }
-
a) Guess what the algorithm does.
-
b) Give an asymptotically (worst case) tight bound for the running time of
the algorithm. Explain your answer.
-
Step by Step Solution
There are 3 Steps involved in it
Get step-by-step solutions from verified subject matter experts
