Question: Consider the following algorithm ALGORITHM Find(A[p..r]) if p == r return A[p] else temp1 = Find(A[p..[(p + r)/2]] temp2 = Find(A[[(p + r)/2] + 1..r])

Consider the following algorithm ALGORITHM Find(A[p..r]) if p == r return

Consider the following algorithm ALGORITHM Find(A[p..r]) if p == r return A[p] else temp1 = Find(A[p..[(p + r)/2]] temp2 = Find(A[[(p + r)/2] + 1..r]) if temp1 lessthanorequalto temp2 return temp1 else return temp2 a. What does this algorithm compute? b. Set up a recurrence relation for the algorithm's basic operation count and solve it. You may assume that the array A has 2^k elements

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