Consider the following algorithm

for $(i=1$;$i{1\mathrm{.}5}^{***}n$;$i++)$

system.out.print$($i$)$;

for $(i=n$;$i1$;$i--)$

system.out.print$($i$)$;

What is the output when $n=1$

Answers:

$.11\mathrm{.}51$

b$.111\mathrm{.}5$

c$.11$

d$.$ None of the above