Consider the following Boolean function:

$F(x,y)=x^{\text{'}}{y}^{\text{'}}+x{y}^{\text{'}}+y(x{y}^{\text{'}})$

where $x^{\text{'}}=$notx,$y^{\text{'}}=$noty

The value of $F(x,y)$ if $y=1$ and $x=1$ is:

$1$

$0$