Consider the following C$-$style code:

int x;

int y;

void f$()\{$

int y $=$ g$($x$)+1$;

h$($y$)$;

$\}$

int g$($int y$)\{$

return y$-$x;

$\}$

void h$($int x$)\{$

printf$("\%$d

$",$ x$+$y$)$;

$\}$

void main$()\{$

x $=2$;

y $=3$;

f$()$;

h$($x$+$y$)$;

$\}$

What does this program print if the language uses static scoping? What does it print with dynamic scoping? Explain why.

Answer: