Question: Consider the following code: begin integer m , n; procedure f; begin integer m: = n; print ( in f - - n =
Consider the following code:
begin
integer m n;
procedure f;
begin
integer m: n;
printin f n printin f m
end;
n; m:
procedure gn: integer;
begin
printin g m
m;
printin g n
n;
f
end;
m : ;
n :; g ; f;
printin main program printin main program n
end;
m; n;
What does this program print if the language uses static scoping? What does it pri each frame, show the local variables including parameters with their currentvale
points
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