Question: Consider the following code segment: System.out.println ( Enter your age: ) ; int age = scanner.nextInt ( ) ; System.out.println ( Enter your

Consider the following code segment:
System.out.println("Enter your age:");
int age = scanner.nextInt () ;
System.out.println("Enter your name:");
String name = scanner. nextLine () ;
There is a logic error with this code. The program will accurately store the value of the user's age into age, but the program does not function appropriately when tasked with getting input from the user and storing it in name.
Which of the following explains why this program will not work properly and how to fix it.
 Consider the following code segment: System.out.println("Enter your age:"); int age =

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