Question: Consider the following code: stack s; s . push ( 1 0 ) ; int x = s . top ( ) ; s .

Consider the following code:
stack s;
s.push(10);
int x = s.top();
s.pop(10);
If we change the type of s to queue, and use front instead of top:
the contents of s and value of x would be unchanged.
the code would no longer compile.
the value of x would not change, but the contents of s would be different.
the code would throw an exception and fail.
Consider the following code: stack s; s . push (

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