Question: Consider the following divide-and-conquer algorithm: Algorithm DCSum( n ) //Input: A positive integer n //Output: ? if n == 1 return n else do half

Consider the following divide-and-conquer algorithm:

Algorithm DCSum(n) //Input: A positive integer n //Output: ? if n == 1 return n else do half = (int)(n/2); return DCSum(half) + DCSum(n - half); end if

What does the algorithm compute and return? Establish and solve the recurrence relation for the total number of additions performed overall.

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