Consider the following.

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}(e^{9x}-\frac{6}{e^{\frac{x}{2}}})dx$

Find a substitution to rewrite the integrand term $e^{9x}$ as $\frac{e^u}{9}du.$

$u=$

$du=(,)dx$

Find a substitution to rewrite the integrand term $-\frac{6}{e^{\frac{x}{2}}}$ as $12e^{v}dv.$

$v=$

$dv=(,)dx$

Evaluate the integral. $($Remember the constant of integration.$)$