Consider the following function and closed interval. f(x) = arctan(2-x), [1, 2] Is f continuous on the closed interval [1, 2]? Yes No If f is differentiable on the open interval (1, 2), find f'(x). (If it is not differentiable on the open interval, enter DNE.) 1 (x-4x+5) f'(x) = Find f(1) and f(2). f(1) = f(2)= 0 Find TL 4 f(b) f(a) b-a f(b) f(a) b-a C = for [a, b]= [1, 2]. I 4 Determine whether the Mean Value Theorem can be applied to f on the closed interval [a, b]. (Select all that apply.) Yes, the Mean Value Theorem can be applied. No, f is not continuous on [a, b]. No, f is not differentiable on (a, b). None of the above. f(b) f(a) If the Mean Value Theorem b-a If the Mean Value Theorem can be applied, find all values of c in the open interval (a, b) such that f'(c) = cannot be applied, explain why not. (Enter your answers as a comma-separated list. Round your answer to four decimal places. If the Mean Value Theorem cannot be applied, enter NA.)