Consider the following function.

$f(x)=\frac{9e^x}{e^x-9}$

Find the value$(s)ofx$ such that $e^x-9=0.(Enter$ your answers $as$ a comma$-$separated list. $Ifan$ answer does not exist, enter DNE.$)$

$x=$

Does there exist a real number $c$ such that $\underset{xc}{lim}\frac{9e^x}{e^x-9}isan$ indeterminate form?

Yes

$No$

Find the following $limits.$

$\underset{x-}{lim}\frac{9e^x}{e^x-9}=$

$\underset{x}{lim}\frac{9e^x}{e^x-9}=$

$x=$

$y=$