Consider the following function. F(x) = 16 -x2/3 Find f(-64) and f(64). 1(-64 ) = F(64) = Find all values c in (-64, 64) such that f'(c) = 0. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) Based off of this Information, what conclusions can be made about Rolle's Theorem? This contradicts Rolle's Theorem, since fis differentiable, f(-64) = ((64), and f'(c) = 0 exists, but c is not in (-64, 64). This does not contradict Rolle's Theorem, since f'(0) = 0, and 0 is in the interval (-64, 64). This contradicts Rolle's Theorem, since ((-64) = ((64), there should exist a number c in (-64, 64) such that f'(c) = 0. This does not contradict Rolle's Theorem, since f'(0) does not exist, and so f is not differentiable on (-64, 64). Nothing can be concluded