Consider the following graph. The function in the graph is a solution of one of the following differential equations. A. y' = 1+xy B. y' = -2xy C. y'-1-2xy Decide which is the correct equation and justify your answer. MY NOTES For points in the first quadrant, the differential equation y' = 1+xy is greater than 1 increases for some points and decreases for other points in the first quadrant and is only increasing To summarize, the graph is the solution to which of the three differential equations? in the first quadrant and is only increasing For points in the first quadrant, the differential equation y' = -2xy is greater than 0 increases for some points and decreases for other points in the first quadrant and is only increasing For points in the first quadrant, the differential equation y' = 1-2xy is equal to 0 increases for some points and decreases for other points . For points in the second quadrant, this differential equation can be greater than, less than or equal to 1 in the second quadrant, this differential equation cannot For points in the second quadrant, this differential equation is equal to 0 in the second quadrant, this differential equation cannot For points in the second quadrant, this differential equation is greater than 0 in the second quadrant, this differential equation can Since the function graphed be the correct equation. X Since the function graphed be the correct equation. . Since the function graphed be the correct equation. OAy'=1+xy OB. y' = -2xy C. y' = 1- 2xy