Consider the following hypothesis test.

H₀: ₁² = ₂²

H_a: ₁² ₂²

(a)

What is your conclusion if

n₁ = 21, s₁² = 8.1, n₂ = 26, and s₂² = 4.0?

Use = 0.05 and the p-value approach.

Calculate the value of the test statistic (to 2 decimals).

The p-value is (use attached table)

Repeat the test using the critical value approach.

What is the rejection rule for this hypothesis test?

Round the critical values to decimal places.

Reject H₀ if F ___________

TABLE 4 F DISTRIBUTION Area or probability Fa Entries in the table give F. values, where a is the area or probability in the upper tail of the F distribution. For example, with 4 numerator degrees of freedom, 8 denominator degrees of freedom, and a .05 area in the upper tail, F.os = 3.84. Numerator Degrees of Freedom Denominator Area in 100 Upper 15 25 30 40 60 1000 20 Degrees of Freedom Tall $7.24 58.20 58.91 59.44 59.86 60.19 61.22 61.74 62.05 62.26 62.53 62.79 63.01 63.30 254.19 .10 39.86 49.50 $3.59 55.83 233.99 236.77 238.88 240.54 241.88 248.02 249.26 250.10 251.14 224.58 230.16 245.95 252.20 993.08 998.09 01.40 1005.60 1009.79 1017.76 199.50 215.71 963.28 968.63 6286.43 6312.97 6333.92 6362.80 647.79 864.15 99.60 21.83 6208.66 6239.86 50.35 052.18 4909 3 4 to 5403.53 5624.26 763.96 5858.95 5928.33 5980.95 6022.40 6055.93 6156.97 9.47 9.4 9.48 9.49 9.37 9.38 9.39 9.42 9.44 9.45 9.46 8.53 9.00 9.25 9.33 9.3. 19.33 19.3 19.37 19.38 19.40 19.4 9.45 19.4 19.47 19.49 18.51 19.00 39.46 39.49 39.50 38.51 39.33 39.36 39.37 39.39 39.40 39.43 39.45 99 48 99 50 99.33 99.36 99.38 99.39 99.40 99.43 99.45 99.46 99.47 99.48 99.49 98.50 3 8 5.20 5.15 5.14 5.13 8.57 8.55 8.53 5.54 8.70 13.96 13.91 10.13 14.73 14.62 14:47 14.25 14.12 26.58 26.14 97.91 27.67 26.87 3.80 3.79 3.78 3.76 3.98 3.95 3.94 5.69 5.66 6.09 8.66 8.36 8.32 8.26 13.47 14.98 14.80 14.66 14.20 13.65 13.58 73 100 1000