Question: Consider the following Java code: interface I { int f(); int g();} abstractclassCimplementsI{publicintf(){return3;}} class D extends C{ public int f() { return 7; } public

Consider the following Java code:

interface I { int f(); int g();}

abstractclassCimplementsI{publicintf(){return3;}} class D extends C{

public int f() { return 7; }

public int g() { return f() + 5 * super.f(); }

}

class E extends D { public int f() { return 11; } } classFextendsE{publicintf(){returnf();}}

//... in some other class, perhaps in main() ... final I x = new D(); System.out.println(x.g()); final I y = new E(); System.out.println(y.g());


a. 1What does this code print? (the twoSystem.out.println()'s)



b. 1 What are the static (compile-time) and dynamic (runtime) types ofx?Static: Dynamic:


c. 1 What are the static and dynamic types ofy?Static: Dynamic:


d. 1In the context of the code above, what happens when you evaluate theexpression

new F().f() (this is legitimate "method chaining")? If there is any problem, what causes it?


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