Question: Consider the following language: L = { | A is a DFA and B is an NFA & L(A) & L(B) & L(A)L(B)=} Show that

Consider the following language: L = {| A is a DFA and B is an NFA & L(A) & L(B) & L(A)L(B)=} Show that L is Turing recognisable. Is the complement of L also Turing recognisable? (Give reasons for your answer.)

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