Consider the following linear program. Max3A + 2B s.L. 1A + 18 = 10 3A+ 1B = 26 1A + 28 = 18 A, B =0 (a) (b) () (d) Use the graphical solution procedure to find the optimal solution. What is the value of the objective function at the optimal solution? at (A, B) =( Assume that the objective ) function coefficient for A changes from 3 to 5. Use the graphical solution procedure to find the new optimal solution. Does the optimal solution change? The extreme point ( ) Select w | optimal. The value of the objective function becomes Assume that the objective function coefficient for A remains 3, but the objective function coefficient for 8 changes from 2 to 4. Use the graphical solution procedure to find the new optimal solution. Does the optimal solution change? The extreme point ( ) Select ~ | optimal. The value of the objective function becomes The computer solution for the linear program in part (a) provides the following objective coefficient range information. Variable Objective | Allowable | Allowable Coefficient | Increase Decrease A 3.00000 3.00000 1.00000 a 2.00000 1.00000 1.00000 Use this objective coefficient range information to answer parts (b) and (c). The objective coefficient range for variable A is to . Since the change in part (b} is | Select | this range, we know the optimal solution | Select | change. The objective coefficient range for variable 8 is to . Since the change in part (c) is | Select this range, we know the optimal solution | Select v | change