Question: Consider the following loop: / / Precondition: ( index = x ) wedge ( x geq 1 ) wedge ( y =

Consider the following loop:
//Precondition: (index=x)\wedge(x\geq1)\wedge(y=0)
while (index>1)
{
index = index/2;
++y;
}
//Postcondition: (index =1)^(2y}\leqx)\wedge(x\mp@subsup{2}{}{y+1}
Suppose we have already proved the first two parts of the postcondition, that is,(index =1) and ((:2yx}. Now we are
trying to prove the last part )(2y+1.
If index
Consider the following loop: / / Precondition: (

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