Consider the following method, which is written in pseudocode:

function bar$($a: int, n: int$)=>$ int:

if n $<1$:

return $1$

else:

x $=1$

while x $<$ n:

a $=$ a $+2$

x $=$ x $+1$

return a $*$ bar$($a$,$ n$-1)$

If you invoke bar with bar$(2,3),$ what is returned by the method?

a$.$

$384$

b$.$

$48$

c$.$

$600$

d$.$

$1344$