Consider the following.

n $+239$Pu $90$Kr $+148$Ce $+2$ n

$($a$)$

Calculate the energy released in the neutron$-$induced fission reaction above, given m$(90$Kr$)=89\mathrm{.}919524$ u and m$(148$Ce$)=147\mathrm{.}924395$ u$.($Assume

$1$ u $=931\mathrm{.}5$ MeV$/$c$2.)$

MeV

$($b$)$

Confirm that the total number of nucleons and total charge are conserved in this reaction.

Ai $=$ Af$=$ Qi $=$ Qf$=$