Consider the following pay-off table where the rows (D1, D2, D3) represent the decisions and the columns (E1, E2, E3) represent the events. The "probability" row provides the probability of each event happening. A negative value means a loss. Also, the D1-E1 and D3-E1 pay-offs are hidden. Using the expected value approach, the optimal decision would be if XXX is and YYY is \begin{tabular}{l} D2, -700, -300 \\ \hline D2, -500, -250 \\ \hline D3, 0,300 \\ \hline D1, 400,0 \\ \hline D1, 200,200 \end{tabular}