Consider the following problem formulation, original tableau, and optimal tableau. Max Z = 3 X1 + 5 X2 + X3 s. t. 8 X1-14 X2 +3 X3 50 + X3 22 -2 X1 +7 X2 X1 + X2 + X3 17 X1, X2, X3 0 Original Tableau X1 X2 X3 S1 S2 RHS S3 -3 -5 -1 0 0 0 0 8 -14 3 1 0 0 50 -2 7 1 0 1 0 22 1 1 1 0 0 1 17 Optimal Tableaul X1 X2 X3 S1 S2 S3 RHS 1 0 0 8/3] 0 2/9 31/9 571/9 0 0 0 7/3 1 22/9 -28/9 458/9 0 0 1 1/3 0 1/9 2/9 56/9 0 1 0 2/3 0 -1/9 7/9 97/9 *Note: Make sure you can see the entire image. The last column should be RHS. 1. The ordered set BV of the problem is: pod N 1 0 0 0 N *Note: Make sure you can see the entire image. The last column should be RHS. 1. The ordered set BV of the problem is: OAnswer not provided OZ,X1,x2,S1 OZ,S1,x2,X1 OZ,X1,x2,X3 OZ,S1,S2,S3 OZ,X2,X1,53 OZ,X2,X3,S3 2. The set NBV of the problem is: OS1,S2,S3,RHS OZ,X1,X2,S2 OX3,S1,S2,RHS OX1, X2,S1,RHS OZ,S1,X2,X1 OAnswer not provided OX3,S2,S3,RHS OX1,S1,S2,RHS 3. The vector for objective function's coefficient for the set BV is: O[1,-3,-5,-1] O[-1,0,0,0] O[1,3,5,1] O[1,0,-5,-3] O[1,-3,-5,0] O[1,-3,-5,-1] OAnswer not provided 4. The vector for objective function's coefficient for the set NBV is: O[1,0,0,0] O[-1,0,0,0] O[1,0,-5,-3] O[0,0,0,0] OAnswer not provided O[1,-3,-5,-1] 5. The matrix B resulting from BV is: O[1,0-5,-3 0,1/-14,8 0,0,7,-2 0,0,1,1] O[1,-5,-3,-1 0,-14,8,3 0,7,-2,1- 0,1,1,1] O[1,-5,-3,0 0,-14,8,1 0,7,-2,0 0,1,1,0] OAnswer not provided