Question: Consider the following program: { int x = 7; void p () { write (x); } void q (void px ()) { int x
Consider the following program: { int x = 7; void p () { write (x); } void q (void px ()) { int x = 4; px (); } void r () { int x = 3; q (p); } { x = 1; P (); q (p); r (); } } What does the program print in case of (i) static scope (and deep binding), (ii) dynamic scope and deep binding, (iii) dynamic scope and shallow binding. Explain by describing how the program is executed.
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The provided code snippet demonstrates how the programs output would differ based on the combination of scoping staticdynamic and binding shallowdeep ... View full answer
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