Consider the following Prolog program using the predicates hasPet$($a$,$ b$)$ to represent that person a owns a pet b and doesNotEat$($a$,$ b$)$ to represent that animal a does not eat animal b$.$

hasPet$($joe$,$ fish$).$

hasPet$($pierre$,$ pig$).$

hasPet$($joe$,$ chameleon$).$

hasPet$($selvi$,$ cat$).$

hasPet$($rich$,$ dog$).$

hasPet$($kumar$,$ turkey$).$

hasPet$($rich$,$ turkey$).$

doesNotEat$($X$,$ Y$)$ :$-$ hasPet$($Z$,$ X$),$ hasPet$($Z$,$ Y$).$