Question: Consider the following recursive function and tree: void printTree ( Node * node ) { if ( node = = NULL ) return; printTree (
Consider the following recursive function and tree:
void printTreeNode node
if node NULL return;
printTreenodeleft;
cout nodekey ;
printTreenoderight;
root
The following code is called:
printTreeroot;
root is a pointer to the node whose key is What is true about the output from cout? Note there may be multiple correct answers, please mark all correct statements. There are no intended errors in the code.
Group of answer choices
is printed before
is printed before
is printed first
is printed before
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