Question: Consider the following RISCV code loop: beq x 1 , x 0 , exit / / if x 1 = x 0 exit subi x

Consider the following RISCV code
loop: beq x1, x0, exit //if x1=x0 exit
subi x1, x1,1//sub 1 from x1
sll x2,x2,1//shift left x2 one position or x2=2*x2
j loop //go to loop
exit:
Assume initially x2=2, and x1=3. Also remember x0 is always zero. What is the final value in x2

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