Question: Consider the following Scheme function foo: (define (foo x) (cond ((null? x) 0) ((not (list? (car x))) (+ 1 (foo (cdr x)))) ((eq? x ())

Consider the following Scheme function foo:

 (define (foo x) (cond

 ((null? x) 0) ((not (list? (car x)))

 (+ 1 (foo (cdr x)))) ((eq? x ()) (foo (car x))) ((eq? x (x)) (foo x)) (#t (+ (foo (car x)) (foo (cdr x))))))

(a) Explain what the function computes and how. Dont just restate the function definition in English explain the algorithm. Hint: not all the code in this function does something useful.

(b) Show the result of executing the expression

 (foo (((a b (c d)) (((d e)) f) g)))

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