Question: Consider the following search method. private static int search (int[] a, int target, int left, int right) { if (left > right) return 1 else

Consider the following search method.

private static int search (int[] a, int target, int left, int right) {

if (left > right)

return 1

else {

int midpoint = (left + right) / 2

if (a[midpoint] == target)

return midpoint

else if (a[midpoint] < target)

return search (a, target, midpoint + 1, right)

else

return search (a, target, left, midpoint - 1)

}

}

Which of the following might be described as the base case(s) for this method to end the recursion?

when the value is found in the middle of the range

if (a[midpoint] == target)

when there are no elements in the specified range of indices

if (left > right)

When the midpoint value is greater than the target

if (a[midpoint] > target)

When the midpoint value is less than the target

if (a[midpoint] < target)

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