Question: Consider the following. sin 3 ( y ) cos 6 ( y ) dy This is an integral of the form sinm ( y )

Consider the following.
sin3(y) cos6(y) dy
This is an integral of the form
sinm(y) cosn(y) dy,
where the power of sine is ---Select---oddeven and the power of cosine is ---Select---oddeven . The strategy for evaluating an integral of this type is to save one ---Select---sinecosine factor and use
sin2(x)=1 cos2(x)
to express the remaining factors in terms of ---Select---sinecosine . Then, use the following substitution.
u =
1cos3(y)
Evaluate the integral. (Use C for the constant of integration.)

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