Consider the following statement:

my$\_$obj$->$myfun$()$;

Why is it not possible from this statement alone to determine which member function myfun$()$will be executed?

Question $4$ options:

Because the variable my$\_$obj may also be stored in an array or a vector

Because the function myfun$()$does not have parameters

Because the variable my$\_$obj is a pointer

Because the object pointed to by my$\_$obj might be a derived object