Consider the following two variable bindings in Lisp:

$($setq x $($a b c d$))$

$($setq y $(1234))$

Using only the variables x and y and the functions car, cdr and cons, provide Lisp S$-$

expressions for generating the following

$(($a $1)($b $2)($c $3)($d $4))$

i have this expression as answerr

$($cons $($cons $($car x$)($car y$))$

$($cons $($cons $($cadr x$)($cadr y$))$

$($cons $($cons $($caddr x$)($caddr y$))$

$($list $($cons $($cadddr x$)($cadddr y$))))))$

i am getting $(($A $.1)($B $.2)($C $.3)($D $.4))$

but actually i want $(($A $1)($B $2)($C $3)($D $4))$

it means without dots can you fix it