Consider the function below:

$1//$ n is the number of ints in art

$2$ void mystery $($ int$*$ arr, int $n)\{$

$3$ int i;

$4$ Stack enqueue ith int in arr into $q*/$

$3$

$12$ while $(!$ isEmptyStack $($ s $)||!$isEmptyQueue$($ q $)\{$

$13$ if $(!$isEmptyStack $(8))\{$

$14$ enqueue $($ q$,$ pop $($ s $))$;

$15$

$16$ else$\{$

$17$ a printf$(\%$od odequeue $($ q$))$;

$18-$

$19\}$

$20$ freeStack $($ s $)$ ;

${?}^{21}$ freequeue $(9)$;

$\}$

$($a$)(2$ points$)$ What is printed by mystery $(\{0,1,2\},3)$ :