Consider the function $f(x)=\frac{3}{11+6x}.$ The goal is to compute $f^{\text{'}}(x)$ using the definition

$f^{\text{'}}(x)=\underset{h0}{lim}\frac{f(x+h)-f(x)}{h}$

a$)$ We have that $\frac{f(x+h)-f(x)}{h}=$

Note for this part your answer may be left unsimplified.

Notice that as $h0,$ this is an indeterminate of the form $\frac{0}{0}.$

b$)$ Simplify the expression in $($a$)$ to get $\frac{f(x+h)-f(x)}{h}=\frac{A}{B},$ where $A$ is a constant and $B$ is a function of $x$ and $h.$

What are the values of A and $B?$

Answer: $[A,B]=$

FORMATTING: Please type your answer in the form $A,B,$ with the square brackets and a comma between A and $B.$ For this question, you must use strict scientific calculator notation: multiplication is written $*$; for example, you must write $2x$ as $2^{**}x$ and $(x+1)(x+2)$ as $(x+1{)}^{**}(x+2)$

c$)$ Finally, we have that

$f^{\text{'}}(x)=\underset{h0}{lim}\frac{f(x+h)-f(x)}{h}=$

$$

FORMATTING: Your answer must be a function of $x.$ Make sire all the formatting is correvt please