Consider the function $f(x)=\frac{x-3}{\sqrt[\phantom{2}]{1+x^2}}$ in the interval $-6,6.$

After constructing a fourth order polynomial $P_4(x)$ which corresponds the approximation of $f(x)$ by taking $16$ equidistant points in $[-6,6],$ find the value of approximate polynomial $P_4(x)$ at the point $x=888\mathrm{.}444$ by using MATLAB.

Your answer:

$-1\mathrm{.}8082e+09$

$1\mathrm{.}8082e+09$

$1\mathrm{.}8182e+09$

$-1\mathrm{.}8182e+09$

$-1\mathrm{.}7082e+09$