Question: Consider the function f ( x ) = - x 2 2 - 1 . . . . In this problem you will calculate 0

Consider the function f(x)=-x22-1.
...
In this problem you will calculate 04(-x22-1)dx by using the definition:
abf(x)dx=limn[i=1nf(xi)x]
The summation inside the brackets is Rn which is the Riemann sum where the sample points are chosen to be the right-hand endpoints of each sub-interval.
Calculate Rn for f(x)=-x22-1 on the interval [0,4] and write your answer as a function of n without any summation signs.
Rn=
lim Rn=
n ->
Consider the function f ( x ) = - x 2 2 - 1 . . .

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