Question: Consider the function f(x) = 3-8x2 on the interval [-4, 5]. Find the average or mean slope of the function on this interval, i.e.

Consider the function f(x) = 3-8x2 on the interval [-4, 5]. Find the average or mean slope of the function on this interval, i.e. f(5)-f(-4)= 5-(-4) By the Mean Value Theorem, we know there exists a C in the open interval (-4, 5) such that f'(c) is equal to this mean slope. For this problem, there is only one C that works. Find it.

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