Question: Consider the function F(x,y,z) defined with the following truth table: Z 0 0 0 0 0 0 F 1 0 1 1 0 1 1

Consider the function F(x,y,z) defined with the following truth table: Z

Consider the function F(x,y,z) defined with the following truth table: Z 0 0 0 0 0 0 F 1 0 1 1 0 1 1 1 1 0 1 0 0 0 1 0 1 0 0 1 1 1 1 0 1 1 Write the algebraic expression of the function in minterm canonical form. Do not use dots () and spacing, the only allowed chracaters are: X, Y, Z, +, ' (prime). Put the minterms in increasing order of their indices

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