Question: Consider the function h (x) = 6x2 +13x+92 and let x>0. 400x+x3+71 Looking at the denominator, as the value of x increases without bound, which

 Consider the function h (x) = 6x2 +13x+92 and let x>0.

400x+x3+71 Looking at the denominator, as the value of x increases without

Consider the function h (x) = 6x2 +13x+92 and let x>0. 400x+x3+71 Looking at the denominator, as the value of x increases without bound, which term will eventually have the highest value? O x3 O 71 None of these They will all be equally high as x increases without bound O 400x

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