Consider the given reaction in which NC is the nucleophile and CH3CN is the solvent. The reactant molecule has a structure with solid and dashed wedge bonds. A solid wedge () is used to show the bond that is above the plane of the paper, and a dashed wedge () is used to show the bond that is behind the plane of the paper. Draw the product of the following reaction: Make sure to draw the correct configuration. SN2 Correct Now that you have determined the mechanism that the given reaction follows, you can determine that the product will be formed by the backside attack of the nucleophile (NC) . The NC ion attacks on the side opposite to the Br atom. As a result, the configuration of the product will be an inversion of the configuration of the reactant. Draw the molecule on the canvas by choosing buttons from the Tools (for bonds), Atoms, and Advanced Template toolbars. The single bond is active by default. Show the appropriate stereochemistry by choosing the dashed or wedged buttons and then clicking a bond on the canvas. Include all hydrogen atoms.

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