Consider the implicit function and its graph. ycos(y+x+x2) = x3 The derivative % is found implicitly. x y' cos (y + x + x2) - ysin (y + x + x2 ) (y' + 1+2x) =3x2 Evaluate the derivative dy . That is, Substitute x = 0 and y = into the derivative, then solve for dx at the point P = (0, 2 3 TT 2 dy = dx \\pFind y' = 3: using implicit differentiation. xzny+y2=y (Express numbers in exact form. Use symbolic notation and fractions where needed. Write your solution as an equation solved for y' in terms of x andfor y.) equation (include y' = in your solution): ' Find y' = dy using implicit differentiation. dx x2 - y2 - 5xy = 13 (Express numbers in exact form. Use symbolic notation and fractions where needed. Assume that 2y + 5x # 0.) =d Find y' = dy using implicit differentiation. x (x2 +306 = 3* (Express numbers in exact form. Use symbolic notation and fractions where needed. Assume that 6(x2 + y)5 1 75 0.)