Question: Consider the improper integrals 1= [sin()dx and J-sin()dx. (a) By 1 making the substitution u = - show that I = X sin u

Consider the improper integrals 1= [sin()dx and J-sin()dx. (a) By 1 making

Consider the improper integrals 1= [sin()dx and J-sin()dx. (a) By 1 making the substitution u = - show that I = X sin u 0 1 u du and J = 1 u using appropriate MacLaurin series, determine whether the integrals I and J exist. 2 sin u 0 du. (b) By

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