Consider the indefinite integral / - tan 0 In(2 cos 0) de For the following type theta for 0 This can be transformed into a basic integral through u-substitution by letting U = cos ( 0 ) X du = -sin (0) x de Performing the substitution yields the integral - tan 0 In(2 cos 0) de = In(2u) x du u Now, evaluate the integral and find an expression for - tan 0 In(2 cos 0) do in terms of 0. Use C for any constant of integration and type theta for 0. - tan 0 In(2 cos () de = - In- (2 cos (0) ) + C