Consider the initial value problem: $$ t^{3} y {\prime prime \prime)-2 t^{2} y"[\prime prime)+3 t y{\prime)-3 y=t^{2}, \quad y(1)=1, y^{\prime) (1)=0, y {\prime \prime} (1)=1 $$ The approximation of $y[\prime}(1.2)5 by using Euler's method with $h=0.1$ is most nearly: $0.25$ $0.26$ $0.28$ $0.27$ SP.SD.437