Question: Consider the initial value problem. x = [1 -5, 2 -1]x, x(2018) = [2, 2] f

Consider the initial value problem.

x = [1 -5, 2 -1]x, x(2018) = [2, 2]

Consider the initial value problem. x = [1 -5, 2 -1]x, x(2018)

\f

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