Question: Consider the integral 24(25 - 4) dx. To find the value of this integral, make the substitution u = x - 4. a) Write (25

 Consider the integral 24(25 - 4) dx. To find the valueof this integral, make the substitution u = x - 4. a)Write (25 - 4) in terms of u: b) This makes x*dax= du c) Re-write the integral in terms of u and du,and find the antiderivative. The antiderivative in terms of u is: +C d) Now back-substitute and write your answer to part (c) interms of x: + CConsider the indefinite integral / 7 - 8dx: This can be transformed into a basic integral by letting uand du da Performing the substitution yields the integral duey Consider the

integral dy: ey + 3 This can be transformed into a basicintegral by letting and du = dy After perfroming the substitution, youobtain the integral duConsider the integral / cot(0) . In(6 sin(0)) de:This can be transformed into a basic integral by letting and du= de After perfroming the substitution, you obtain the integral duarccos (4y)Consider the integral - dy: 1 -1692 This can be transformed intoa basic integral by letting and du = dy After perfroming thesubstitution, you obtain the integral du(In(z)) 6 Consider the indefinite integral dz:Z This can be transformed into a basic integral by letting and

Consider the integral 24(25 - 4) dx. To find the value of this integral, make the substitution u = x - 4. a) Write (25 - 4) in terms of u: b) This makes x*dax = du c) Re-write the integral in terms of u and du, and find the antiderivative. The antiderivative in terms of u is: + C d) Now back-substitute and write your answer to part (c) in terms of x: + CConsider the indefinite integral / 7 - 8 dx: This can be transformed into a basic integral by letting u and du da Performing the substitution yields the integral duey Consider the integral dy: ey + 3 This can be transformed into a basic integral by letting and du = dy After perfroming the substitution, you obtain the integral duConsider the integral / cot(0) . In(6 sin(0)) de: This can be transformed into a basic integral by letting and du = de After perfroming the substitution, you obtain the integral duarccos (4y) Consider the integral - dy: 1 -1692 This can be transformed into a basic integral by letting and du = dy After perfroming the substitution, you obtain the integral du(In(z)) 6 Consider the indefinite integral dz: Z This can be transformed into a basic integral by letting and du dz Performing the substitution yields the integral duConsider the indefinite integral dx: (202 + 6) 2 This can be transformed into a basic integral by letting u and du dx Performing the substitution yields the integral du6e 6x Consider the indefinite integral dx: (e62 + 5) 4 This can be transformed into a basic integral by letting and du dx Performing the substitution yields the integral duVa + 9 Consider the indefinite integral da: Vx6 This can be transformed into a basic integral by letting u and du dx Performing the substitution yields the integral du

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