Consider the integral

${\displaystyle \underset{\phantom{}}{\overset{\phantom{}}{}}}\frac{x^2}{(x-1)(x^2+1)}dx$

Find related partial fractions

$\frac{x^2}{(x-1)(x^2+1)}=\frac{A}{x-1}+\frac{Bx+C}{x^2+1}$

$A=1,B=1,C=0$

$A=0,B=1,C=1$

$A=1,B=1,C=1$