Consider the limit

$$lim$$x$$$$

$25$x$4+15$x$2+6$

$7$x$2+9$x $+10$

For large values of x$,$ the above fraction is approximately:

$25$x$4+15$x$2+6$

$7$x$2+9$x $+10$

$$

Use the above approximation to find the limit$.$

$$lim$$x$$$$

$25$x$4+15$x$2+6$

$7$x$2+9$x $+10$

$=$