Consider the line with these parametric equations:

$x=-2t8$

$y=-t6$

$z=6t-4$

One set of symmetric equations for this line is

$\frac{x-8}{-2}=\frac{y-y_0}{b}=\frac{z-z_0}{c}$

where $y_0=z_0=b=$ and $c=$

Another set of symmetric equations for this line is

$\frac{x}{2}=\frac{y-y_1}{b}=\frac{z-z_1}{c}$

where $y_1=,z_1=,b=$ and $c=$